1=x^2-14x+49

Solution for 1=x^2-14x+49 equation:

1=x^2-14x+49

We move all terms to the left:

1-(x^2-14x+49)=0

We get rid of parentheses

-x^2+14x-49+1=0

We add all the numbers together, and all the variables

-1x^2+14x-48=0

a = -1; b = 14; c = -48;
Δ = b2-4ac
Δ = 142-4·(-1)·(-48)
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-2}{2*-1}=\frac{-16}{-2}
=+8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+2}{2*-1}=\frac{-12}{-2}
=+6
$